Question

In a particular experiment, a glass undergoes adiabatic expansion satisfying the equation VT³ = constant. The ratio of specific heats g is –

• A. 4
• B. 3
• C. $\frac{5}{3}$
• D. $\frac{4}{3}$

Answer 1

Answer: (D)

$\frac{4}{3}$

Answer 2

V^g–1 T = const. or V $T^{\frac{1}{\gamma - 1}}$ = const

$\frac{1}{\gamma - 1}$ = 3 or 1 = 3g – 3, g = 4/3