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Question

Physics Question on electrostatic potential and capacitance

In a parallel plate capacitor, the capacity increases if

A

area of the plate is decreased

B

distance between the plates increases

C

area of the plate is increased

D

dielectric constant decrease

Answer

area of the plate is increased

Explanation

Solution

In a parallel plate capacitor, the capacity of capacitor,
C=kε0AdC = \frac{k \varepsilon_0 A}{d}
therefore C \propto A
So, the capacity of capacitor increase if area of the plate is increased.