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Physics Question on Nuclear physics

In a nuclear fission process, a high mass nuclide (A ≈ 236) with binding energy 7.6 MeV/Nucleon dissociated into middle mass nuclides (A ≈ 118), having binding energy of 8.6 MeV/Nucleon. The energy released in the process would be ____ MeV.

Answer

Energy released Q=BEProduct−BEReactantQ = \text{BE}_{\text{Product}} - \text{BE}_{\text{Reactant}}:

Q=2×118×8.6−236×7.6Q = 2 \times 118 \times 8.6 - 236 \times 7.6

=236×(8.6−7.6)=236 MeV= 236 \times (8.6 - 7.6) = 236 \, \text{MeV}