Question: In a normal spinel types structure, the oxide ions are arranged in ccp whereas 1/8 tetrahedral holes...

Question

In a normal spinel types structure, the oxide ions are arranged in ccp whereas 1/8 tetrahedral holes are occupied by Zn2+ ions and 50% of octahedral holes are occupied by Fe3+ ions. The formula of the compound is –

Answer 1

Solution

In one unit cell no. of O^2– = 4

The no. of Zn²⁺ = $\frac{1}{8}$ × 8 = 1

The no. of Fe³⁺ = $\frac{1}{2}$ × 4 = 2

\ molecular formula of given spinel structure is ZnFe₂O₄