Question

In a multi-electron atom, which of the following orbitals ? described by the three quantum numbers will have the same energy in the absence of magnetic and electric fields ? (A) $n = 1,\,l = 0, \,m = 0$ (B) $n = 2,\,l = 0, \,m = 0$ (C) $n = 2, \,l = 1,\, m = 1$ (D) $n = 3,\,l = 2,\, m = 1$ (E) $n = 3,\,l = 2, \,m = 0$

• A. (D) and (E)
• B. (C) and (D)
• C. (B) and (C)
• D. (A) and (B)

Answer 1

Answer: (A)

(D) and (E)

Answer 2

(A) 1s $\quad$ $\quad$(B) 2s (C) 2p $\quad$ $\quad$(D) 3d (E) 3d In the absence of any field, 3 d in (D) and (E) will be of equal energy.