Question

In a mixture, two enantiomers are found to be present in $85\%$ and $15\%$ respectively. The enantiomeric excess $(e, e)$ is

• A. $85\%$
• B. $15\%$
• C. $70\%$
• D. $60\%$

Answer 1

Answer: (C)

$70\%$

Answer 2

$15 \%$ will form racemic mixture with another $15 \%$. Hence, the enantiomeric excess is $=(85-15)=70 \%$