Question
Question: In a mixture of \({K_2}S{O_4}\) and \(MgS{O_4}\), the mass percentage of \({K_2}S{O_4}\)is 80%. Its ...
In a mixture of K2SO4 and MgSO4, the mass percentage of K2SO4is 80%. Its mol-fraction in the mixture is:
1. 0.66
2. 0.75
3. 0.80
4. 0.87
Solution
The mole fraction is calculated by the moles of solute divided by the total number of moles of solute and solvent or total moles of the mixture. The number of solutes is calculated by dividing the mass with the molecular mass.
Complete answer: Given,
Mass percentage of K2SO4 is 80%.
In a 100 % mixture, of K2SO4 and MgSO4, 80% of K2SO4 is present and the remaining 20% of MgSO4 is present.
Mass percent means in 100 g of mixture 80 g of K2SO4 is present and 20 g of MgSO4 is present.
To find out the mole fraction of the compounds present in the mixture, first the moles of the respective compound is calculated.
The formula for calculating the moles of the compound is shown below.
n=Mm
Where,
n is the number of moles of the compound
m is the mass of compound
M is the molecular mass of the compound.
The molar mass of K2SO4 is 174.25g/mol.
To calculate the moles of K2SO4, substitute the values of mass and molecular mass in the equation.
⇒n=174.25g/mol80g
⇒n=0.459mol
The molecular mass of MgSO4 is 120.36 g/mol.
To calculate the moles of MgSO4, substitute the values of mass and molecular mass in the equation.
⇒n=120.36g/mol20g
⇒n=0.166mol
The formula for calculating the mole fraction is shown below.
XA=nA+nBnA
Where,
XA is the mole fraction of compound A.
nA is the number of moles of compound A.
nBis the number of moles of compound B.
To calculate the mole fraction of K2SO4, substitute the values in the above equation.
⇒X=0.459+0.1660.459
⇒X=0.6250.459
⇒X=0.75
Thus, the mole fraction of K2SO4 is 0.75.
Therefore, the correct option is 2.
Note: The mass percentage is the mass of compound divided by the total mass multiplied by 100. The mole fraction of both the compounds in the mixture can be calculated by the same formula but differently.