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Question: In a mixture of gases, the volume content of a gas is ![](https://cdn.pureessence.tech/canvas_9.png?...

In a mixture of gases, the volume content of a gas is at STP. Calculate the number of molecules of the gas in 1 L of the mixture.

A

1.613×10231.613 \times 10 ^ { 23 }

B

6.023×10236.023 \times 10 ^ { 23 }

C

1.61×10271.61 \times 10 ^ { 27 }

D

1.61×10191.61 \times 10 ^ { 19 }

Answer

1.61×10191.61 \times 10 ^ { 19 }

Explanation

Solution

: Volume of gas in 1 L

=0.06100=6×10−4 L= \frac { 0.06 } { 100 } = 6 \times 10 ^ { - 4 } \mathrm {~L}

Number of molecules of CO2\mathrm { CO } _ { 2 } =n×NA= \mathrm { n } \times \mathrm { N } _ { \mathrm { A } }

6×10−422.4×6.023×1023=1.61×1019\frac { 6 \times 10 ^ { - 4 } } { 22.4 } \times 6.023 \times 10 ^ { 23 } = 1.61 \times 10 ^ { 19 }