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Question: In a meter bridge shown in the figure, the balance point is found to be 40cm from and A. If a resist...

In a meter bridge shown in the figure, the balance point is found to be 40cm from and A. If a resistance of 10Ω10\Omega is connected in series with R, a balance point is obtained 60cm from A. Calculate the value of R and S.

Explanation

Solution

Meter bridge: A meter bridge also called a slide wire bridge is an instrument that works on the principle of a Wheatstone bridge. A meter bridge is used in finding the unknown resistance of a conductor as that of in a Wheatstone bridge.

Complete step-by-step solution:
Given,
R=10Ω10\Omega
When a balance point is at 40cm, we have
RS=4010040\Rightarrow \dfrac{R}{S} = \dfrac{{40}}{{100 - 40}}
Simplify,
RS=4060\Rightarrow \dfrac{R}{S} = \dfrac{{40}}{{60}}
RS=23\Rightarrow \dfrac{R}{S} = \dfrac{2}{3}
3R=2S\Rightarrow 3R = 2S …(1)
When a resistance of 10Ω10\Omega is added in series with R, then equivalent resistance at R isR=R+10{R^`} = R + 10
Now, balance point is at 60 cm. So, we have
R+10S=6010060\Rightarrow \dfrac{{R + 10}}{S} = \dfrac{{60}}{{100 - 60}}
R+10S=6040\Rightarrow \dfrac{{R + 10}}{S} = \dfrac{{60}}{{40}}
R+10S=32\Rightarrow \dfrac{{R + 10}}{S} = \dfrac{3}{2}
2R+20=3S\Rightarrow 2R + 20 = 3S
2R3S=20\Rightarrow 2R - 3S = 20 …(2)
Solving equation 1 and 2
S=12Ω12\Omega
R=8Ω8\Omega

Note: The device required in finding the unknown resistance of a conductor using the meter bridge are- meter bridge, resistance box, galvanometer, unknown resistance of length 1m, screw gauge, connecting wire, jockey, and one way key. A scale is attached to the block.