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Question

Physics Question on thermal properties of matter

In a mercury thermometer, the ice point (lower fixed point) is marked as 1010^{\circ} and the steam point (upper fixed point) is marked as 130130^{\circ}. At 40C40^{\circ} C temperature, what will this thermometer read?

A

7878 ^{\circ}

B

6666 ^{\circ}

C

6262 ^{\circ}

D

5858 ^{\circ}

Answer

5858 ^{\circ}

Explanation

Solution

x1013010=40100\frac{x-10}{130-10}=\frac{40}{100}
100x1000=4800100 x-1000=4800
100x=5800100 x=5800
x=58x=58^{\circ}