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Question

Mathematics Question on Probability

In a meeting 70% of the members favour a certain proposal,30%being opposed.A member is selected at a random and we let X=0 if he is in favour.Find E(X) and Var (X).

Answer

It is given that P(X = 0) = 30% =30100=0.3\frac{30}{100}=0.3

P(X=1)=70%=70100=0.7\frac{70}{100}=0.7

Therefore, the probability distribution is as follows.

X01
P(X)0.30.7

xt pt xtpt xtpt2
0 30100\frac{30}{100}
1701007010070100\frac{ 70}{100}\frac{70}{100}\frac{ 70}{100}
ptxt=70/100ptxt2=70100∑ptxt=70/100 ∑ptxt2=\frac{70}{100}
E(X)=Mean=ptxt=70100=0.7E(X)=Mean=∑ptxt=\frac{70}{100}=0.7
Vrience(X)=ptxt2(ptxt)2=70100(70100)2=71049100=21100=0.21Vrience(X)=∑ptxt2-(∑ptxt)2=\frac{70}{100}-(\frac{70}{100})2=\frac{7}{10}-\frac{49}{100}=\frac{21}{100}=0.21

=0.21