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Physics Question on Electric charges and fields

In a medium of dielectric constant K, the electric field is E⃗\vec{E} . If ∈0\in_0 is permittivity of the free space, the electric displacement vector is

A

KE⃗∈0\frac{K \vec{E}}{\in_0}

B

E⃗K∈0\frac{ \vec{E}}{ K \in_0}

C

∈0E⃗K\frac{\in_0 \vec{E}}{K}

D

K∈0E⃗K \in_0 \vec{E}

Answer

K∈0E⃗K \in_0 \vec{E}

Explanation

Solution

Electric displacement vector, D⃗=εE⃗\vec{D} = \varepsilon \vec{E} As, ε=ε0K    ∴ D⃗=ε0KE⃗\varepsilon = \varepsilon_0 K \, \, \, \, \therefore \, \vec{D} = \varepsilon_0 K \vec{E}