Question
Question: In a medium of dielectric constant \( K \) , the electric field is \( \vec E \) . If \( {\varepsilon...
In a medium of dielectric constant K , the electric field is E . If ε0 is the permittivity of free space, the electric displacement vector is:
(A)\dfrac{{K\vec E}}{{{\varepsilon _0}}} \\\
(B)\dfrac{{\vec E}}{{k{\varepsilon _0}}} \\\
(C)\dfrac{{{\varepsilon _0}\vec E}}{k} \\\
(D)K{\varepsilon _0}\vec E \\\
Solution
Hint : In order to solve this question, we are going to first find the permittivity of the given medium from the value of the permittivity of the free space ε0 and the dielectric constant K . After that the displacement current is found from the permittivity so obtained and the electric field vector as given.
Formula used: If the dielectric constant of a medium is K and the permittivity of free space is ε0
Then, the permittivity of the medium is given by
ε=Kε0
If E is the electric field inside a medium and ε is the permittivity of the medium, then, the displacement current vector of the medium is given by
D=εE
Complete Step By Step Answer:
As we are given that the dielectric constant of the medium is K , thus, the permittivity of the given medium can be written as the product of the dielectric constant and the permittivity of the free space.
i.e.
ε=Kε0
Now the displacement current vector is mathematically the product of the permittivity of the medium and the electric field E
So, D=εE
Now putting the value of the permittivity, ε in the above relation, we get
D=Kε0E
Thus, the option (D)Kε0E is the correct answer.
Note :
In electromagnetism, displacement current density is the quantity ∂t∂D appearing in Maxwell's equations that is defined in terms of the rate of change of D , the electric displacement field. It depends directly on the value of the electric field applied across the medium and also the permittivity of the medium.