Question

In a mathematics test given to 15 students, the following marks (out of 100) are recorded:
$41,39,48,52,46,62,54,40,96,52,98,40,42,52,60.$ Find the mean, median and mode of this data.

Answer 1

Here the given question need to solve the man, median and mode for the given data of student for any exam, here we have to use the formulae of all the three requirements which is asked for and then after simplifying we can have the final solution of the data.

Formulae Used:
$\Rightarrow mean = \dfrac{{summation\,of\,all\,the\,given\,data}}{{total\,number\,of\,data}}$

Complete step by step solution:
The given question need to find the mean, median and mode for the given data for which we have to use the formulae for all the three requirements, on solving we get:
$\Rightarrow mean = \dfrac{{summation\,of\,all\,the\,given\,data}}{{total\,number\,of\,data}}$
On using the formulae for our question, solving we get:
$\Rightarrow mean = \dfrac{{41 + 39 + 48 + 52 + 46 + 62 + 54 + 40 + 96 + 52 + 98 + 40 + 42 + 52 + 60}}{{15}} = \dfrac{{822}}{{15}} = 54.8$
Final mean solution for the given data is “54.8”
To find the median for the data we need to see the rules for the median, to find the median for the given data, the median says that for any given set of data if the set of numbers are odd then the middle number of the set of data is the median.
Hence the 8th term of the set of data is the median which is “40”.
For finding the mode for the data we have to find the most repeating numbers, in the set of data the number “40” is repeated two times so is the median for the given question.

Note: To solve the question we have to use the standard formulae of mean, median and mode and accordingly we have to put the values in the formulae to find the final solution for the given set of questions.