Question

In a lossless transformer an alternating current of 2 amp is flowing in the primary coil. The number of turns in the primary and secondary coils are 100 and 20 respectively. The value of the current in the secondary coil is

• A. 0.08 A
• B. 0.4 A
• C. 5 A
• D. 10 A

Answer 1

Answer: (D)

10 A

Answer 2

$\frac{N_{s}}{N_{p}} = \frac{i_{p}}{i_{s}}$ ⇒ $i_{s} = i_{p} \times \frac{N_{p}}{N_{s}} = 2 \times \frac{100}{20} = 10\mspace{6mu} A$