Question

In a lift, when will the apparent weight become twice the actual weight?

Answer 1

Before going to the question let us first know about apparent weight. The apparent weight of an object is a feature of items that relates to how heavy it is in physics. When the force of gravity acting on an object is not balanced by an equal but opposing normal force, the apparent weight of the object will differ from the weight of the object.

Complete step-by-step solution:
The elevator and the occupant are starting their journey on a lower floor in this example. The elevator, often known as a lift, moves upward. Because the person's inertia would prefer him to remain stationary, the elevator floor and scale must push up on him to propel him higher with the elevator. To stimulate the person's bulk upward, the scale must press upward with greater power on the person. This occurs when the scale and the human come into closer contact.

As a result, the Normal Force is stronger, and the reading on the scale is more than the genuine weight. $F = ma$ operating on the person, according to Newton's 2nd Law.
The person's total acceleration is upward (with the elevator). As a result, the parameter $'ma'$ is positive (upward).
The force of gravity acting downward, $- W = - mg$ , and the supporting normal force are the only external forces acting on the person.
while the lift is travelling up with g acceleration.
$R{\text{ }} = {\text{ }}m{\text{ }}\left( {g + a} \right){\text{ }} = {\text{ }}m{\text{ }}\left( {g + g} \right){\text{ }} = {\text{ }}2mg$
As a result, the perceived weight becomes twice the actual weight when climbing up and speeding up (acceleration and is positive).
Note: The weight you 'feel' is your apparent weight. When you're falling, you'll have a sense of weightlessness. As a result, the apparent weight is zero. When you're in an elevator that's speeding up, you'll notice that you're getting heavier. As a result, the apparent weight increases.