Question

In a large building, there are 15 bulbs of 40, W, 5 bulbs of 100 W, 5 fans of $80\, W$ and 1 heater of $1\, kW$. The voltage of the electric mains is $220 \,V$. The minimum capacity of the main fuse of the building will be :

• A. 8 A
• B. 10 A
• C. 12 A
• D. 14 A

Answer 1

Answer: (C)

12 A

Answer 2

$15 \times 40+5 \times 100+5 \times 80+1000=V \times I$
$600+500+400+1000=220\,I$
$I=\frac{2500}{220}=11.36$
$I=12\,A$