Question

In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of $2.5$ % per hour. Find the bacteria at the end of $2$ hours if the count was initially $5,06,000$.

Answer 1

The initial count of bacteria is given as $5,06,000$.
Bacteria at the end of $2$ hours = $506000\bigg(1+\frac{2.5}{100}\bigg)^2$

= $506000\bigg(1+\frac{1}{40}\bigg)^2 = 5060000 × \frac{41}{40} × \frac{41}{40}$
$531616.25 = 5,31,616 \;(approx)$

Thus, the count of bacteria at the end of $2$ hours will be $5,31,616 \;(approx.)$.