Question
Question: In a L-R circuit, the value of L is \(\left( \frac{0.4}{\pi} \right)\mspace{6mu} henry\) and the val...
In a L-R circuit, the value of L is (π0.4)6muhenry and the value of R is 30 ohm. If in the circuit, an alternating e.m.f. of 200 volt at 50 cycles per sec is connected, the impedance of the circuit and current will be
A
11.4Ω,17.5A
B
30.7Ω,6.5A
C
40.4Ω,5A
D
50Ω,4A
Answer
50Ω,4A
Explanation
Solution
Z=R2+X2=R2+(2πfL)2
=(30)2+(2π×50×π0.4)2=900+1600=50Ω
i=ZV=50200=4ampere