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Question: In a L-R circuit, the value of L is \(\left( \frac{0.4}{\pi} \right)\mspace{6mu} henry\) and the val...

In a L-R circuit, the value of L is (0.4π)6muhenry\left( \frac{0.4}{\pi} \right)\mspace{6mu} henry and the value of R is 30 ohm. If in the circuit, an alternating e.m.f. of 200 volt at 50 cycles per sec is connected, the impedance of the circuit and current will be

A

11.4Ω,17.5A11.4\Omega,17.5A

B

30.7Ω,6.5A30.7\Omega,6.5A

C

40.4Ω,5A40.4\Omega,5A

D

50Ω,4A50\Omega,4A

Answer

50Ω,4A50\Omega,4A

Explanation

Solution

Z=R2+X2=R2+(2πfL)2Z = \sqrt{R^{2} + X^{2}} = \sqrt{R^{2} + (2\pi fL)^{2}}

=(30)2+(2π×50×0.4π)2=900+1600=50Ω\sqrt{(30)^{2} + \left( 2\pi \times 50 \times \frac{0.4}{\pi} \right)^{2}} = \sqrt{900 + 1600} = 50\Omega

i=VZ=20050=4amperei = \frac{V}{Z} = \frac{200}{50} = 4ampere