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Question

Physics Question on Atoms

In a hydrogen like atom electron makes transition from an energy level with quantum number nn to another with quantum number (n1).Ifn>>1(n - 1). If n > > 1, the frequency of radiation emitted is proportional to

A

1n3\frac{1}{n^{3}}

B

1n\frac{1}{n}

C

1n2\frac{1}{n^{2}}

D

1n3/2\frac{1}{n^{3/2}}

Answer

1n3\frac{1}{n^{3}}

Explanation

Solution

In a hydrogen like atom, when an electron makes an transition from an energy level with n to n - 1, the frequency of emitted radiation is
υ=RcZ2[1(n1)21n2]=RcZ2(2n1)n2(n1)2\upsilon=RcZ^{2}\left[\frac{1}{\left(n-1\right)^{2}}-\frac{1}{n^{2}}\right]=\frac{RcZ^{2}\left(2n-1\right)}{n^{2}\left(n-1\right)^{2}}
As n > > 1
υ=RcZ22Nn4=2RcZ2n3\therefore\quad\upsilon=\frac{RcZ^{2} 2N}{n^{4}}=\frac{2RcZ^{2}}{n^{3}} or υ1n3\upsilon\propto\frac{1}{n^{3}}