Question

In a hydrogen atom, the radius of n^th Bohr orbit is$r_{n}$ The graph between log $(r_{n}/r_{1})$ and long n will be

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Answer 2

We know that $r_{n} \propto n^{2}or(r_{n}/r_{1}) = n^{2}$

So, $\log(r_{n}/r_{1}) = 2\log n$

Hence the graph between $\log(r_{n}/r_{1})$ and log n will be a straight line passing through origin

The positive slope is given by $\tan\theta = 2$