Question

In a hydrogen atom, the radius of $n^{th}$ Bohr orbit is $r_n$. The graph between $log(r_n/r_1)$ and $logn$ will be

• A.
• B.
• C.
• D.

Answer 1

Answer: (A)

Answer 2

We know that $r_n \propto n^2$ or $(r_n/r_1) = n_2$ So, $log(r_n /r_1) = 2\,log\, n$ Hence, the graph between $log(r_n /r_1)$ and $log\,n$ will be a straight line passing through origin. The positive slope is given by $tan\,\theta = 2$.