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Question: In a hydrogen atom, the distance between the electron and proton is \(2.5 \times 10^{- 11}m\). The ...

In a hydrogen atom, the distance between the electron and proton is 2.5×10−11m2.5 \times 10^{- 11}m.

The electrical force of attraction between them will be.

A

2.8×10−7⥂N2.8 \times 10^{- 7} ⥂ N

B

3.7×10−7N3.7 \times 10^{- 7}N

C

6.2×10−7N6.2 \times 10^{- 7}N

D

9.1×10−7N9.1 \times 10^{- 7}N

Answer

3.7×10−7N3.7 \times 10^{- 7}N

Explanation

Solution

F=9×109×1.6×10−19×1.6×10−19(2.5×10−11)2=3.7×10−7NF = \frac{9 \times 10^{9} \times 1.6 \times 10^{- 19} \times 1.6 \times 10^{- 19}}{(2.5 \times 10^{- 11})^{2}} = 3.7 \times 10^{- 7}N