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Question: In a hydrogen atom, an electron moves in a circular orbit of radius \(5.2 \times 10 ^ { - 11 } \math...

In a hydrogen atom, an electron moves in a circular orbit of radius 5.2×10−11 m5.2 \times 10 ^ { - 11 } \mathrm {~m} and produces a magnetic induction of 12.56 T at its nucleus. The current produced by the motion of the electron will be (Given

A

6.53×10−36.53 \times 10 ^ { - 3 } ampere

B

13.25×10−1013.25 \times 10 ^ { - 10 } ampere

C

9.6×1069.6 \times 10 ^ { 6 } ampere

D

1.04×10−31.04 \times 10 ^ { - 3 } ampere

Answer

1.04×10−31.04 \times 10 ^ { - 3 } ampere

Explanation

Solution

B=μ04π⋅2πir⇒12.56=10−7×2π×i5.2×10−11B = \frac { \mu _ { 0 } } { 4 \pi } \cdot \frac { 2 \pi i } { r } \Rightarrow 12.56 = 10 ^ { - 7 } \times \frac { 2 \pi \times i } { 5.2 \times 10 ^ { - 11 } }