Question

In a heat engine, the temperature of the source of sink are 500 K and 375 K. If the engine consumes 25 × 105 J per cycle, the work done per cycle is

• A. 6.25 × 105 J
• B. 3 × 105 J
• C. 2.19 × 105 J
• D. 4 × 104 J

Answer 1

Answer: (A)

6.25 × 105 J

Answer 2

: here,

$\therefore \eta = 1 - \frac { T _ { 2 } } { T _ { 1 } } = 1 - \frac { 375 } { 500 } = 0.25$

=25%