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Question

Mathematics Question on Permutations

In a group of 6 boys and 4 girls, a team consisting of four children is formed such that the team has atleast one boy. The number of ways of forming a team like this is

A

159

B

209

C

200

D

240

Answer

209

Explanation

Solution

The team has atleast one boy
= Total case - No anyone boy
=10C46C0={ }^{10} C_{4}-{ }^{6} C_{0}
=10×9×8×74×3×21=2101=209=\frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2}-1=210-1 =209