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Question: In a given system of units, 1 unit of mass= 2kg, 1 unit of length = 5m and 1 unit of time = 5 sec. t...

In a given system of units, 1 unit of mass= 2kg, 1 unit of length = 5m and 1 unit of time = 5 sec. then in this system, 1N represented:
(A). 52\dfrac{5}{2} units of force
(B). 25\dfrac{2}{5} units of force
(C). 2 units of force
(D). 12\dfrac{1}{2} units of force

Explanation

Solution

Hint: International unit of force is newton. Force is defined as a product of mass and acceleration. Convert kilogram into 1 unit of mass, meter into 1 unit of length and second into 1 unit of time.

Complete step by step solution:
Dimension of force is given by [M][L][T2][M][L][{{T}^{-2}}]
1 N is represented as kg m/s2\text{kg m}/{\text{{s}}^{2}}.
Therefore,
1 N =[M][L][T2][M][L][{{T}^{-2}}]
1N=(1kg)(1m)(1s2)1N=\dfrac{(1kg)(1m)}{(1{{s}^{2}})} -------(1)
Values of 1 unit of mass = 2kg, 1 unit of length = 5m and 1 unit of time = 5sec can be written as,
1 unit of mass = 2kg
1 unit of mass = 2×1kg2\times 1kg
So 1kg = 12unit of mass\dfrac{1}{2} \text{unit of mass}
1 unit of length = 5m
1 unit of length = 5×1m5\times 1m
So, 1m=15unit of length1m=\dfrac{1}{5} \text{unit of length}
1 unit of time = 5sec
I unit of time = 5×1sec5\times 1\sec
1sec=15unit of time1\sec =\dfrac{1}{5} \text{unit of time}
Now put values of 1 unit of mass = 2kg, 1 unit of length = 5m and 1 unit of time = 5sec in equation (1)i.e. in above formula,
1 N = (12unit of mass)(15unit of mass)(15unit of mass)\dfrac{(\dfrac{1}{2} \text{unit of mass})(\dfrac{1}{5} \text{unit of mass})}{(\dfrac{1}{5} \text{unit of mass})}
1 N=52unit of mass=\dfrac{5}{2} \text{unit of mass}
So one newton of force is 52\dfrac{5}{2} unit of force.
So, the answer is 52\dfrac{5}{2} unit of force

Note: SI unit of force is newton. It is represented by N. one newton is also represented as a kilogram meter per second square. Force is a vector quantity which has both magnitude and direction. Force is dependent on mass and acceleration.