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Question

Physics Question on Current electricity

In a given circuit, each cell has an emf of 0.15V0.15\, V and internal resistance of 0.25Ω0.25 \, \Omega . Find the current in the circuit.

A

0.12 A

B

0.012 A

C

0.045 A

D

0.45 A

Answer

0.045 A

Explanation

Solution

Number of cell (n)=3(n)=3
Number of row (m)=10(m)=10
Internal resistance =0.25Ω=0.25 \Omega
R=10ΩR=10 \,\Omega
E=0.15VE =0.15 V
We know that,
i=mnEnr+mRi=\frac{m n E}{n r+m R}
i=10×3×0.153×0.25+10×10\Rightarrow i=\frac{10 \times 3 \times 0.15}{3 \times 0.25+10 \times 10}
i=4.50.75+100\Rightarrow i=\frac{4.5}{0.75+100}
i=4.5100.75\Rightarrow i=\frac{4.5}{100.75}
i=0.0446\Rightarrow i=0.0446
i=0.045A\Rightarrow i=0.045\, A