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Question

Mathematics Question on Sequence and series

In a G.PG.P. of even number of terms, the sum of all terms is 55 times the sum of the odd terms. The common ratio of the G.PG.P. is

A

45\frac{-4}{5}

B

15\frac{1}{5}

C

44

D

5-5

Answer

44

Explanation

Solution

Let us consider a G.P.a,ar,ar2,...G.P. a, ar, ar^{2},... with 2n2 n terms, we have a(r2n1)r1\frac{a\left(r^{2n } -1\right)}{r-1} =5a((r2)n1)r21= \frac{5a \left(\left(r^{2}\right)^{n}-1\right)}{r^{2}-1} (since common ratio of odd terms will be r2 r^2 and number of terms will be nn) a(r2n1)r1 \Rightarrow \frac{a\left(r^{2n} -1\right)}{r-1} =5a(r2n1)(r21) = 5 \frac{a\left(r^{2n} -1\right)}{\left(r^{2}-1\right)} a(r+1)=5a\Rightarrow a\left(r+1\right) = 5a r=4 \Rightarrow r= 4