Question
Mathematics Question on Sequence and series
In a G.P. of even number of terms, the sum of all terms is 5 times the sum of the odd terms. The common ratio of the G.P. is
A
5−4
B
51
C
4
D
−5
Answer
4
Explanation
Solution
Let us consider a G.P.a,ar,ar2,... with 2n terms, we have r−1a(r2n−1) =r2−15a((r2)n−1) (since common ratio of odd terms will be r2 and number of terms will be n) ⇒r−1a(r2n−1) =5(r2−1)a(r2n−1) ⇒a(r+1)=5a ⇒r=4