Question

In a full wave rectifier in which input voltage is represented by ${\text{V = }}{{\text{V}}_{\text{M}}}{\text{sin}}\omega {\text{t}}$ then peak inversion voltage of non-conducting diode will be:
A) ${\text{ }} - {{\text{V}}_{\text{M}}}$
B) ${\text{ }}\dfrac{{{{\text{V}}_{\text{M}}}}}{2}$
C) ${\text{ }}2{{\text{V}}_{\text{M}}}$
D) 0

Answer 1

Rectifier: It is an electrical device used to convert alternating current (AC), which periodically reverses its direction, to direct current (DC).
The flow of the current is in only one direction. Inverter carries out the reverse operation.

Rectification: The process performed by the rectifier is known as rectification since it "straightens" the direction of the current.

Complete step by step solution:
Half wave rectifiers that use only half-wave of the input alternating current cycle, full-wave rectifiers utilize full-wave.
The entire secondary voltage appears across the non-conducting diode, therefore peak inverse voltage for full-wave rectifier is $2{{\text{V}}_{\text{M}}}$.
By using a full-wave rectifier with a center-tapped transformer, it generates the voltages that are in phase with each other.
According to the question ${\text{V = }}{{\text{V}}_{\text{M}}}{\text{sin}}\omega {\text{t}}$,
So we can say that the peak inversion voltage is $2{{\text{V}}_{\text{M}}}$
The full-wave rectifier has more efficiency compared to that of a half-wave rectifier; there is no loss in the output power.
There will be no loss in the input voltage signal in the full-wave rectifier.
Ripple factor in the full- wave rectifier is less compared to that of the half-wave rectifier.

Hence the correct option is $\left( {\text{C}} \right)$.

Note: Vacuum chemical tube, wet chemical cells, mercury-arc valves, stacks of copper and selenium oxide plates, semiconductor devices use the full wave rectifier.
The components of direct current power supplies and high voltage direct current power transmission systems have many uses in rectifiers.
Rectifier is used to detect the presence of a flame.
The biasing conditions of p-n junction’s diode state that during forward bias the diode is in conducting mode acting like a closed circuit.
During reverse bias orientation the diode is in non-conducting or acting as an open circuit.
By this way the diode acts as a switch.