Solveeit Logo

Question

Question: In a full wave junction diode rectifier the input ac has rms value of 20 V. the transformer used is ...

In a full wave junction diode rectifier the input ac has rms value of 20 V. the transformer used is a step up transformer having primary and secondary turn ration 1 : 2 The dc voltage in the rectified output is

A

12 V

B

24 V

C

36 V

D

42 V

Answer

36 V

Explanation

Solution

: here, inputVrms=20VV_{rms} = 20V

Peak value of input voltage

Vo=2Vrms=2×20=28.28VV_{o} = \sqrt{2}V_{rms} = \sqrt{2} \times 20 = 28.28V

Since the transformer is a step up transformer having transformer ratio 1:21:2the maximum value of output voltage of the transformer applied to the diode will be

Vo=2×Vo=2×28.28VV_{o}^{'} = 2 \times V_{o} = 2 \times 28.28V

\thereforedc voltage =2Voπ=2×2×28.2822/7=36V= \frac{2V_{o}^{'}}{\pi} = \frac{2 \times 2 \times 28.28}{22/7} = 36V