Question

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is

• A. 6
• B. 7
• C. 8
• D. 12

Answer 1

Answer: (B)

7

Answer 2

Let $x$ be the upper limit and $y$ be the lower limit. Since the mid value of the class is 10 $\therefore \, \frac{x+y}{2} = 10 \:\: \Rightarrow \:\:\:\:\:\:\: x + y = 20$ ....(1) and $x - y = 6$ (width of the class = 6) ...(2) By solving (1) and (2), we get y = 7. Hence, lower limit of the class is 7.