Solveeit Logo

Question

Question: In a flask of volume V litres, \(0.2\)mol of oxygen, \(0.4\)mol of nitrogen, 0.1 mol of ammonia and ...

In a flask of volume V litres, 0.20.2mol of oxygen, 0.40.4mol of nitrogen, 0.1 mol of ammonia and 0.30.3mol of helium are enclosed at 270C27^{0}C. If the total pressure exerted by these non-reacting gases is one atmosphere, the partial pressure exerted by nitrogen is.

A

0.10.1atmosphere

B

0.20.2 atmosphere

C

0.30.3 atmosphere

D

0.40.4 atmosphere

Answer

0.40.4 atmosphere

Explanation

Solution

: PN2=0.40.2+0.4+0.1+0.3×1=0.4P_{N2} = \frac{0.4}{0.2 + 0.4 + 0.1 + 0.3} \times 1 = 0.4atm

(\thereforepartial pressure = mole fraction × total pressure)