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Question: In a fission process, nucleus A divides into two nuclei B and C, their binding energies being \(E_{a...

In a fission process, nucleus A divides into two nuclei B and C, their binding energies being Ea,6muEbE_{a},\mspace{6mu} E_{b}and EcE_{c} respectively. Then

A

Eb=Ec=EaE_{b} = E_{c} = Ea

B

Eb+Ec>EaE_{b} + E_{c} > E_{a}

C

Eb+Ec<EaE_{b} + E_{c} < E_{a}

D

Eb,6muEc=EaE_{b},\mspace{6mu} E_{c} = E_{a}

Answer

Eb+Ec>EaE_{b} + E_{c} > E_{a}

Explanation

Solution

Eb+Ec>EaE_{b} + E_{c} > E_{a}