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Chemistry Question on Chemical Kinetics

In a first order reaction 80% of the reactant at an instant was reduced to 8% in 4606 seconds. The rate constant of the reaction is

A

2.303×10−4s−12.303 \times 10^{-4} s^{-1}

B

4.606×10−3s−14.606 \times 10^{-3} s^{-1}

C

5.000×10−3s−15.000 \times 10^{-3} s^{-1}

D

5.000×10−4s−15.000 \times 10^{-4} s^{-1}

Answer

5.000×10−4s−15.000 \times 10^{-4} s^{-1}

Explanation

Solution

Answer (d) 5.000×10−4s−15.000 \times 10^{-4} s^{-1}