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Question: In a double slit experiment using light of wavelength 600 nm, the angular width of a fringe on a dis...

In a double slit experiment using light of wavelength 600 nm, the angular width of a fringe on a distant screen ;is 0.10. The spacing between the two slits is :

A

3.44×10−4m3.44 \times 10^{- 4}m

B

1.54×10−4m1.54 \times 10^{- 4}m

C

1.54×10−3m1.54 \times 10^{- 3}m

D

1.44×10−3m1.44 \times 10^{- 3}m

Answer

3.44×10−4m3.44 \times 10^{- 4}m

Explanation

Solution

: Angular width of fringe

∴d=λθ=600×10−93.14/1800=3.44×10−4m\therefore d = \frac{\lambda}{\theta} = \frac{600 \times 10^{- 9}}{3.14/1800} = 3.44 \times 10^{- 4}m