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Question

Physics Question on Wave optics

In a double slit experiment, the distance between the slits is dd. The screen is at a distance DD from the slits. If a bright fringe is formed opposite to one of the slits, its order is

A

dλ\frac{d}{\lambda}

B

λ2dD\frac{\lambda^{2}}{dD}

C

D22λd\frac{D^{2}}{2\lambda d}

D

d22Dλ\frac{d^{2}}{2D\lambda}

Answer

d22Dλ\frac{d^{2}}{2D\lambda}

Explanation

Solution

When a bright fringe is formed opposite to one of the slits, x=d2x = \frac{d}{2} Path difference =xdD= \frac{xd}{D} =d2×dD=d22D= \frac{d}{2} \times \frac{d}{D} = \frac{d^2}{2D} If it is nthn^{th} order bright fringe, Path differnce, nλ=d22Dn\lambda = \frac{d^2}{2D} or n=d22Dλ n = \frac{d^2}{2D\lambda}