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Question: In a diatomic molecule the bond distance is \(1 \times 10^{- 8}\)cm. its dipole moment is \(1.2D.\) ...

In a diatomic molecule the bond distance is 1×10−81 \times 10^{- 8}cm. its dipole moment is 1.2D.1.2D. What is the fractional electronic charge on each atom?

A

0.500.50

B

1.2×10−101.2 \times 10^{- 10}

C

0.250.25

D

1.21.2

Answer

0.250.25

Explanation

Solution

: Partial charge

=

=1.2×10−18esucm1×10−8cm\frac{= 1.2 \times 10^{- 18}esucm}{1 \times 10^{- 8}cm}

=1.2×10−10esu1.2 \times 10^{- 10}esu

Fractional charge

=1.2×10−104.8×10−10=0.25= \frac{1.2 \times 10^{- 10}}{4.8 \times 10^{- 10}} = 0.25

(4.8×10−104.8 \times 10^{- 10}is a theoretical value of μ\mu)