Question

In a defective 6 faced die with numbers 1 to 6 inscribed,probability of odd is 2 times that of even. What is the probability to gt number 5 in single throw?

• A. $\frac{2}{9}$
• B. $\frac{4}{81}$
• C. $\frac{1}{3}$
• D. $\frac{1}{9}$

Answer 1

Answer: (A)

$\frac{2}{9}$

Answer 2

Prob of even + Prob of odd = 1 (total probability)
Prob of even + 2 (Prob of even) = 1
3(Prob of even) = 1

Prob of even = $\frac{1}{3}$

So, prob of odd = $\frac{2}{3}$

Since there are 3 odd numbers {1,3,5}.

So, Prob of getting 5 is $\frac{1}{3}$

Hence, getting 5 ( odd ) in a single throw is = $\frac{2}{3}\times\frac{1}{3}=\frac{2}{9}$.
So the correct option is (A)