Question
Question: In a DABC, if a, b, c and A are given, then there are two D’s with third sides c<sub>1</sub> and c<s...
In a DABC, if a, b, c and A are given, then there are two D’s with third sides c1 and c2, then (c1 – c2) is –
A
Ab sin A
B

C
2a2−b2sin2A
D
2ab sin A
Answer
2a2−b2sin2A
Explanation
Solution
a2 = b2 + c2 – 2bc cos A
̃ c2 – 2bc cos A + (b2 – a2) = 0
Clearly c1 and c2 are roots of equation
c1 + c2 = 2b cos A, c1c2 = b2 – a2
\ c1 – c2 =
= 4b2cos2A−4(b2−a2)
=
= 2a2−b2sin2A .