Question

In a Cu-voltameter , mass deposited in 30s is m gm. If the time-current graph is shown in the following figure

What is the electrochemical equivalent of Cu ?

• A. m/2
• B. m/3
• C. m/4
• D. $\frac{m}{63.5}$

Answer 1

Answer: (B)

m/3

Answer 2

Total current passed in 30 sec.

= $\frac{1}{2}$ × 100 × 10 + 100 × 10 + 100 × 10 + $\frac{1}{2}$

× 100 × 10

= 3 × 100 × 10 mA × s

= 3000 × 10^–3 amp s = 3 C

W = $\frac{EQ}{F}$ or $\frac{W}{Q}$ = $\frac{E}{F}$ = Z = $\frac{m}{3}$