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Question

Question: In a concave mirror experiment, an object is placed at a distance \(x _ { 2 }\) from the focus. The ...

In a concave mirror experiment, an object is placed at a distance x2x _ { 2 } from the focus. The focal length of the mirror would be

A

x1x2x _ { 1 } x _ { 2 }

B

x1x2\sqrt { x _ { 1 } x _ { 2 } }

C

x1+x22\frac { x _ { 1 } + x _ { 2 } } { 2 }

D

x1x2\sqrt { \frac { x _ { 1 } } { x _ { 2 } } }

Answer

x1x2\sqrt { x _ { 1 } x _ { 2 } }

Explanation

Solution

Given v=(f+x2)v = \left( f + x _ { 2 } \right)

The focal length f=uvu+v=(f+x1)(f+x2)(f+x1)+(f+x2)f = \frac { u v } { u + v } = \frac { \left( f + x _ { 1 } \right) \left( f + x _ { 2 } \right) } { \left( f + x _ { 1 } \right) + \left( f + x _ { 2 } \right) }

On solving, we get f2=x1x2f ^ { 2 } = x _ { 1 } x _ { 2 } or f=x1x2f = \sqrt { x _ { 1 } x _ { 2 } }