Question

In a compound, oxide ions are arranged in cubic close packing arrangement. Cations A occupy one-sixth of the tetrahedral voids and cations B occupy one-third of the octahedral voids. The formula of the compound is

• A. A2BO3
• B. AB2O3
• C. A2B2O2
• D. ABO3

Answer 1

Answer: (D)

ABO3

Answer 2

no. of oxide ions = 4

no. of A particles = $\frac{1}{6} \times 8$=$\frac{4}{3}$

no. of B particles = $\frac{1}{3} \times 4$ = $\frac{4}{3}$

so formula is A4/3 B4/3O4 or ABO3