Question

In a company, 20% of the employees work in the manufacturing department. If the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company, then the ratio of the average salary obtained by the manufacturing employees to the average salary obtained by the non-manufacturing employees is

• A. 6 : 5
• B. 4 : 5
• C. 5 : 4
• D. 5 : 6

Answer 1

Answer: (B)

4 : 5

Answer 2

Assume that there are $100x$ employees in the organization overall, and that each employee's wage is 100y.
The manufacturing department employs 20% of the workforce, and the combined salary of all manufacturing staff members is one-sixth of the total salary received by all employees inside the organization.
Therefore, there are 20x employees in the manufacturing department overall, and their combined compensation is
$\left(\frac{100y}{6}\right)\left(\frac{100y}{6} \times 20x\right) = \frac{5y}{6x}$ is the average salary in the manufacturing division.
In the nonmanufacturing department, the total number of workers is 80x, and their combined salary is $\frac{500y}{6}$
As a result, the nonmanufacturing department's average income is equal to
$\frac{500y}{6} \times 80x = \frac{25y}{24x}$
The ratio is so as follows: $\frac{5y}{6x} : \frac{25y}{24x}$
$120: 150 = 4:15.$
B is the right choice.