Question

In a common-base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor ($\beta$) will be :

• A. $49$
• B. $50$
• C. $51$
• D. $48$

Answer 1

Answer: (A)

$49$

Answer 2

$\beta= \frac{I_{C}}{I_{g}}$ and $I_{g} +I_{g}$ $\therefore\,\beta=\frac{I_{C}}{I_{g}-I_{C}}=\frac{5.488}{5.60-5.488}=49$