Question

In a common-base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor $\left(\beta\right)$ will be :

• A. 49
• B. 50
• C. 51
• D. 48

Answer 1

Answer: (A)

49

Answer 2

$\beta=\frac{I_{c}}{I_{B}} \, and \, I_{E}=I_{c}+I_{B}$ $\therefore\, \beta=\frac{I_{C}}{I_{E}-I_{C}}=\frac{5.488}{5.60-5.488}=49$