Question

In a common base amplifier circuit, calculate the change in base current if that in the emitter current is 2 mA and α = 0.98

• A. 0.04 mA
• B. 1.96 Ma
• C. 0.98 Ma
• D. 2 Ma

Answer 1

Answer: (A)

0.04 mA

Answer 2

$\Delta i_{c} = \alpha\Delta i_{e} = 0.98 \times 2 = 196mA$

∴ $\Delta i_{b} = \Delta i_{e} - \Delta i_{c} = 2 - 1.96 = 0.04mA$