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Question: In a closed system : A (s) \(\rightleftarrows\) 2B (g) + 3C (g), if the partial pressure of C is dou...

In a closed system : A (s) \rightleftarrows 2B (g) + 3C (g), if the partial pressure of C is doubled, then partial pressure of B will be

A

Two times the original pressure

B

One half of its original value

C

122\frac{1}{2\sqrt{2}}times to the original value

D

22\sqrt{2} times to the original value

Answer

122\frac{1}{2\sqrt{2}}times to the original value

Explanation

Solution

Kp = (2p)2 ื (3p)3 = 27 ื 4 p5 where p is the original press.

A (s) \rightleftarrows 2B (g) + 3C

p 6p

\ (p)2 ื (6p)3 = 27 ื 4p5

or (p)2 =27×4p533×23p3\frac{27 \times 4p^{5}}{3^{3} \times 2^{3}p^{3}} = p22\frac{p^{2}}{2}

\ p = p2\frac{p}{\sqrt{2}} = final partial press.of B

\ p2p\frac{p^{'}}{2p} = finalpartialpressofBinitialpartialpressofB\frac{finalpartialpressofB}{initialpartialpressofB} = p22p\frac{p}{2\sqrt{2}p}

= 122\frac{1}{2\sqrt{2}}