Question: In a circus there are ten cages for accommodating ten animals. Out of these four cages are so small ...

Question

In a circus there are ten cages for accommodating ten animals. Out of these four cages are so small that five out of 10 animals cannot enter into them. In how many ways will it be possible to accommodate ten animals in these ten cages

Answer 1

Solution

At first we have to accommodate those 5 animals in cages which can not enter in 4 small cages, therefore number of ways are ⁶P₅. Now after accommodating 5 animals we left with 5 cages and 5 animals, therefore number of ways are 5!. Hence required number of ways = ⁶P₅ x 5! = 86400.