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Question: In a certain university, the percentage of Hindus, Muslims and Christians among students is \(50,25\...

In a certain university, the percentage of Hindus, Muslims and Christians among students is 50,2550,25 and 2525 respectively. If 50%50\% of Hindus, 90%90\% of Muslims and 80%80\% of Christians are smokers, find the probability that a randomly selected smoker student in Muslim.

Explanation

Solution

In this question we are given the percentage of students of each community and also the percentage of smokers in each community, and by that we can find the total no. of smokers as total no. of students is given and the no. of smokers in each community is also given, so by that we can find the probability that a randomly selected smoker student in Muslim, by using the formula,
PP (Finding a Muslim smoker) == No. of Muslim smokersTotal no. of smokers\dfrac{\text{No. of Muslim smokers}}{\text{Total no. of smokers}}

Complete step-by-step answer:
In this question first of all we will start solving this question by enlisting the given information.
So, it is given in the question that,
Percentage of Hindus, Muslims and Christians among students is 50,2550,25 and 2525 respectively in a certain university. 50%50\% of Hindus, 90%90\% of Muslims and 80%80\% of Christians are smokers.
From this information let us assume that total no. of students is xx
So, we from given information we can say that
No. of Hindus == 50%50\% of xx
\Rightarrow No. of Hindus == 50100(x)\dfrac{{50}}{{100}}\left( x \right)
\Rightarrow No. of Hindus == 0.5x0.5x ……..(i)
No. of Muslims == 25%25\% of xx
\Rightarrow No. of Muslims == 25100(x)\dfrac{{25}}{{100}}\left( x \right)
\Rightarrow No. of Muslims == 0.25x0.25x ……….(ii)
No. of Christians== 25%25\% of xx
\Rightarrow No. of Christians == 25100(x)\dfrac{{25}}{{100}}\left( x \right)
\Rightarrow No. of Christians == 0.25x0.25x ………..(iii)
Now, we will calculate the no. of smokers in each community from the given information using (i), (ii) & (iii)
Now, as it is given that 50%50\% of Hindus, 90%90\% of Muslims and 80%80\% of Christians are smokers.
So, No. of Hindu smokers == 50%50\% of No. of Hindus
\Rightarrow No. of Hindu smokers == 50%50\% of 0.5x0.5x {putting value of No. of Hindus from equation (i)}
\Rightarrow No. of Hindu smokers == 50100(0.5x)\dfrac{{50}}{{100}}\left( {0.5x} \right)
\Rightarrow No. of Hindu smokers == 0.5(0.5x)=0.25x0.5\left( {0.5x} \right) = 0.25x …..(iv)
Also, No. of Muslim smokers == 90%90\% of xx
\Rightarrow No. of Muslim smokers == 90%90\% of 0.25x0.25x {putting value of No. of Muslims from equation (ii)}
\Rightarrow No. of Muslim smokers == 90100(0.25x)\dfrac{{90}}{{100}}\left( {0.25x} \right)
\Rightarrow No. of Muslim smokers == 0.9(0.25x)=0.225x0.9\left( {0.25x} \right) = 0.225x ……....(v)
Similarly, No. of Christian smokers == 80%80\% of xx
\Rightarrow No. of Christian smokers == 80%80\% of 0.25x0.25x {putting value of No. of Christians from equation (ii)}
\Rightarrow No. of Christian smokers == 80100(0.25x)\dfrac{{80}}{{100}}\left( {0.25x} \right)
\Rightarrow No. of Christian smokers == 0.8(0.25x)=0.2x0.8\left( {0.25x} \right) = 0.2x ……....(vi)
Now as we have derived no. of smokers in each community, so we can find the probability of finding a randomly selected smoker student in Muslim, which could be founded by using the formula
PP (Finding a Muslim smoker) == (No. of Muslim smokers) // (Total no. of smokers)
Here, Total no. of smokers == No. of Hindu smokers ++ No. of Muslim smokers ++ No. of Christian smokers
\Rightarrow As we have proved above that
No. of Hindu smokers == 0.25x0.25x, No. of Muslim smokers == 0.225x0.225x, No. of Christian smokers == 0.2x0.2x
\Rightarrow By putting the corresponding values we get
Total no. of smokers =0.25x+0.225x+0.2x = 0.25x + 0.225x + 0.2x
\Rightarrow Total no. of smokers =0.675x = 0.675x
So, now we will find the probability of Muslim smokers,
PP (Finding a Muslim smoker) == (No. of Muslim smokers) // (Total no. of smokers)
As we have derived above that
No. of Muslim smokers == 0.225x0.225x, Total no. of smokers =0.675x = 0.675x
Now putting the corresponding values we get
PP (Finding a Muslim smoker) =0.225x0.675x = \dfrac{{0.225x}}{{0.675x}}
\Rightarrow PP (Finding a Muslim smoker) =13 = \dfrac{1}{3}

The probability is equal to 13\dfrac{1}{3}.

Note: The alternative ways to do this question is by constructing a Venn diagram from the given information, then firstly find the smokers in each community and then find the probability of Muslim smokers by dividing No. of Muslim smokers by Total no. of smokers.